CDBL Programming Example
The following example demonstrates how the precision of the numeric
expression affects the result of using CDBL:
X = 7/9
X# = 7/9
PRINT X
'Both X# and CDBL(X) will be accurate to only 7 decimal
'places, because 7/9 is evaluated in single precision.
PRINT X#
PRINT CDBL(X)
'Accurate to 15 decimal places.
PRINT 7#/9#
Sample Output
.7777778
.7777777910232544
.7777777910232544
.7777777777777778